Work required to give motion to a homogeneous cylinder?

A homogeneous cylinder of radius 20 cm and

mass 55 kg is rolling without slipping along a

horizontal floor at 6 m/s.



How much work was required to give it this

motion? Answer in units of kJ.Work required to give motion to a homogeneous cylinder?The cylinder has both translational and rotational kinetic energies and the sum of these must be the work required.



KE = (1/2)Mv^2 = (1/2)(55)(6^2) = 990 J



Kr = (1/2)Iw^2

where I = the moment of inertia and w = the amgular rotation rate



I = (1/2)Mr^2 = (1/2)(55)(0.2^2) = 1.1

w =v/r = 6/.2 = 30



Kr = (1/2)(1.1)(30^2) = 495 J



Work required = KE + Kr = 990 + 495 J

Work required = 1485 J = 1.485 kJ