Once a 25 kg crate is in motion on a horizontal floor, a horizontal force of 52 N keeps the crate moving with?

Once a 25 kg crate is in motion on a horizontal

floor, a horizontal force of 52 N keeps the crate

moving with a constant velocity.

The acceleration of gravity is 9.81 m/s2 .

What is 渭k, the coefficient of kinetic fric-

tion, between the crate and the floor?Once a 25 kg crate is in motion on a horizontal floor, a horizontal force of 52 N keeps the crate moving with?渭k= Ff/Fn



Fn = m x g = 25 x 9.81 = 245.25N

Since the crate is moving with a constant velocity, it is neither speeding up nor slowing down, so the Fa = Ff so 52N = 52N. Therefore:

Ff = 52N



渭k= Ff/Fn

= 52N/245.25N

= 0.212



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