A 14 kg table initially at rest on a horizontal floor requires a 124 N horizontal force to set it in motion. O?

A 14 kg table initially at rest on a horizontal floor requires a 124 N horizontal force to set it in motion. Once the table is in motion, a 67 N horizontal force keeps it moving at a constant velocity. What is the coefficient of kinetic friction between the table and floor?



Can someone please help me out with an answer AND how to get the answer with it?A 14 kg table initially at rest on a horizontal floor requires a 124 N horizontal force to set it in motion. O?weight of table

= 14 g N

= 137.34 N



when it is in motion, it is subjected to kinetic friction 67N



coefficient of kinetic friction between the table and floor



= 67 / 137 .34



= 0.4878



answer